Published by:
CGP EDU Academic Team
Published on: August 21, 2026
A first order reaction has a rate constant of 2.303 x 10 -3 s -1 . The time required for 40 g of this reactant to reduce to 10 g will be [Given that logic 2 = 0.3010]
Text Solution
Verified by ExpertsThe correct answer is:
Half life for first order reaction is calculated by-
Hair lire period, 
=300.91s
Now, 40g t 1/2 20 g t 1/2 10g
So, 40 g substance requires 2 half-life periods to reduce upto 10 g
Time taken in reduction = 2 x 300.91 s
= 601.82
602s
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